IP Subnetting

• IP without subnetting
• On IP issues without subneting
• IP with subneting
• IP subneting with VLSM
• notation network

IP without subnetting

• Maximum number of hosts in a network based on IP class

Problems that arise on the network without subneting

• Topology / hardware should be the same
• Collisions (collisions of data packets between hosts) more often
• Trouble setting up a network
• Prone to eavesdropping

IP Subnetting,

• Created a network subnets by configuring the subnet mask

example 1

Compare the IP address 10.10.1.1 without subneting (subnetmask

Default = 255.0.0.0) with a subnet mask if subneting = 255 255 255 248!

answer

Network address is calculated by operating a logical AND between the IP address with subnetmasknya

IP address 00001010 00001010 00000001 00000001

Subnetmask 11111111 11111111 11111111 11111000 AND

Network ID 00001010 00001010 00000001 00000000

1. Network ID 10.10.1.0
2. Number of IP in a network

IP-IP Address and bernetwork bersubnetmask same ID

IP address 00001010.00001010.00000001.00000000 = 10.10.1.0

IP address 00001010.00001010.00000001.00000001 = 10.10.1.1

IP address 00001010.00001010.00000001.00000010 = 10.10.1.2

IP address 00001010.00001010.00000001.00000011 = 10.10.1.3

IP address 00001010.00001010.00000001.00000100 = 10.10.1.4

IP address 00001010.00001010.00000001.00000101 = 10.10.1.5

IP address 00001010.00001010.00000001.00000110 = 10.10.1.6

IP address 00001010.00001010.00000001.00000111 = 10.10.1.7

SM 11111111.11111111.11111111.11111000 AND

00001010.00001010.00000001.00000000 Net ID

   3.  Total IP = 8

   4.  The number of IP that can be used host = 8-2 = 6

   5.  Range of host IP = 10.10.1.1-10.10.1.6

example 2

You have a stock of IP 202.10.1.0 - 202.20.1.255. You want to create a subnet

the maximum number of host computer 30. Define the subnetmask

used, and the whole subnet which is formed

Answer:

1. The maximum number of hosts needed 32 = 30 so that the IP (1 fruit for the network ID and a fruit for the broadcast ID)
2. Subnetmask (last segment) that is used is 256-32 = 224, so subnetmasknya is 255.255.255.224
3. Subnets are formed 256/32 = 8 subnets